Question 107479
If loga(7x+1)=loga(4x+16),
then (7x+1)=(4x+16)
{{{(7x+1)=(4x+16)}}}
{{{3x=15}}}
{{{x=5}}}
Check your answer.
loga(7x+1)=loga(4x+16)
loga(7(5)+1)=loga(4(5)+16)
loga(36)=loga(36)
True statement. Good answer. 
b.) 5