Question 1159715
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An alternative to the standard algebraic method for solving this kind of problem....<br>
Consider the least common multiple of the two times, which is 60 hours.<br>
In 60 hours, Ron could do this job 60/20=3 times and Landon could do it 60/30=2 times.<br>
So in 60 hours the two together could do the job 3+2=5 times.<br>
So the amount of time it would take them together to do the one job is 60/5 = 12 hours.<br>