Question 1159688
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(a)  P = {{{(5/20)*(7/19)*(6/18)}}} = {{{(1/4)*(7/19)*(1/3)}}} = {{{7/228}}} = 0.030702.     <U>ANSWER</U>



(b)  I interpret these words "in any order", as if they relate to each such a triple.


     P = {{{(C[5]^1*C[7]^2)/C[20]^3}}} = 


               Next,  {{{C[5]^1}}} = 5;   {{{C[7]^2}}} = {{{(7*6)/2}}} = 7*3 = 21;   {{{C[20]^3}}} = {{{(20*19*18)/3}}} = 20*19*6 = 2280.


       = (therefore, I continue) = {{{(5*21)/2280}}} = {{{21/456}}} = {{{7/152}}} = 0.0460.      <U>ANSWER</U>
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Solved.