Question 1159695


{{{sqrt(x + 4) > 2 + sqrt(x)}}}........square both sides


{{{x + 4 > (2 + sqrt(x))^2}}}

{{{x + 4 > 4 + 4sqrt(x)+x}}}

{{{cross(x) + cross(4) > cross(4) + 4sqrt(x)+cross(x)}}}

{{{0 > 4sqrt(x)}}}

or

 {{{4sqrt(x)<0}}} -> since {{{4>0}}}, inequality will be true only if {{{sqrt(x)<0}}}

=> so, no solution exist because {{{sqrt(x)>=0}}} for all real numbers