Question 1159646
Will use a 90% interval, not a 91% one
half-interval for a proportion is z(0.95)*sqrt(p*(1-p)/n)
p hat is used here which is 202/250=0.808
half-interval is 1.645*sqrt(0.808*0.192/250)=1.645*0.0249=0.0410
90%CI is (0.767, 0.849) or (0.77, 0.85)