Question 1159659
.
<pre>

It is the binomial type probability distribution problem.



The number of trial n= 100; the probability of the success trial is  2% = 0.02,  and the number of success trial k = 2. 


P = {{{C[100]^2*0.02^2*(1-0.02)^98}}} = {{{((100*99)/(1*2))*0.02^2*0.98^98}}} = 0.2734.     <U>ANSWER</U>
</pre>

Solved.