Question 1159655

In triangle {{{PQR}}},
  {{{m}}} < {{{Q = 103}}} degrees,  
{{{PQ = 11.2}}}, and 
{{{QR = 13.1}}}
 To the nearest tenth, what is {{{PR}}}?


{{{PR=sqrt((PQ)^2+(QR)^2-2*PQ*QR*cos(Q))}}}

{{{PR=sqrt((11.2)^2+(13.1)^2-2*11.2*13.1*cos(103))}}}

{{{PR=sqrt(125.44+171.61-293.44*(-0.2249511))}}}

{{{PR=sqrt(297.05+66.0097)}}}

{{{PR=sqrt(363.0597)}}}

{{{PR=19.1}}}