Question 1159601
Please help me solve this equation:  Log (15-5x)-1=(Log 3x-2)
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You should say "Solve for x."

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Log (15-5x)-1=(Log 3x-2)
Assuming "common logs," base 10:
Log (15-5x)- log(10) = (Log 3x-2)
Log ((15-5x)/10) = (Log 3x-2)
(15-5x)/10 = 3x-2
15-5x = 10*(3x-2) = 30x - 20
35 = 35x
x = 1