Question 1159512
in case you have this:

{{{(1/5)(9 +2) +3 = (1/4) (4-d) + 1}}}

{{{(1/5)(11) +3 = (4-d)/4 + 1}}}

{{{11/5 +3 -1= (4-d)/4 }}}

{{{11/5 +2= (4-d)/4 }}}.....both sides multiply by {{{4}}}

{{{4(11/5) +2*4= 4-d}}}

{{{44/5 +8= 4-d}}}

{{{d=4-44/5 -8}}}

{{{d=-64/5}}}

{{{d=-12.80}}}


in case you have this:

{{{1/5(9 +2) +3 = 1/4(4-d) + 1}}}

{{{1/55 +3 = 1/(16-4d) + 1}}}

{{{1/55 +3-1 = 1/(16-4d) }}}

{{{1/55 +2 = 1/(16-4d) }}}

{{{1/55 +110/55 = 1/(16-4d) }}}

{{{111/55= 1/(16-4d) }}}....cross multiply


{{{(16-4d)111= 1* 55}}}

{{{16-4d= 55/111}}}

{{{16-55/111=4d}}}

{{{1721/111=4d}}}

{{{1721/(4*111)=d}}}

{{{d=1721/444}}}

{{{d=3.88}}}