Question 1159477

The point ({{{-4}}},{{{k}}}) and ({{{2}}},{{{1.75}}}) lie in the graph of

{{{ y=x+b}}}........use given point ({{{2}}},{{{1.75}}}) 

{{{ 1.75=2+b}}}......solve for {{{b}}}

{{{ 1.75-2=b}}}

{{{ b=-0.25}}}

so far equation is

{{{ y=x-0.25}}}.......use given point ({{{-4}}},{{{k}}})

{{{ k=-4-0.25}}}.....solve for {{{k}}}

{{{ k=-4.25}}}


->given point ({{{-4}}},{{{k}}}) is ({{{-4}}},{{{-4.25}}})


check it on a graph:


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(-4,-4.25,.12), locate(-4,-4.25,p(-4,-4.25)),
circle(2,1.75,.12), locate(2,1.75,p(2,1.75)),
 graph( 600, 600, -10, 10, -10, 10, x-0.25)) }}}