Question 1159480
Assuming random sample, normality 
probability of this occurring (could also be a hypothesis test, but what is wanted is not stated).
z=(x-mean)/sigma/sqrt(n)
=(26-30)/1.5/sqrt (30)
=-4*sqrt(30)/1.5

=-14.61
This has a p-value of <<0.0001, in this case essentially 0.

If the hypothesis is that the two are the same, it is rejected. ]
If the hypothesis is that college students watch more or the same, and the alternative is that they don't, that hypothesis would also be rejected.