Question 1159443


{{{P(t)=P[0]*e^(r*t)}}}

given: 

{{{P[0]=1200}}}

{{{R=4}}}%->{{{r=0.04}}}

want to double->{{{P(t)=2400}}}



{{{2400=1200*e^(0.04*t)}}}

{{{e^(0.04*t)=2400/1200}}}

{{{e^(0.04*t)=2}}}

{{{ln(e^(0.04*t))=ln(2)}}}

{{{(0.04*t) ln(e)=ln(2)}}}..........{{{ln(e)=1}}}

{{{0.04*t=ln(2)}}}

{{{t=ln(2)/0.04}}}


{{{t}}}≈{{{17.329}}} years