Question 1159320
Jotham needs 70 liters of a 50% alcohol solution. He has a 30% solution and an 80% solution available. How many liters of the 30% solution and how many liters of the 80% solution should he mix to make the 50% solution?
<pre><s>Tutor @IKLEYN is correct about equal amounts being mixed when % of desired mixture is midway between %s of available solutions. 
In her explanation she uses 50% as the desired solution, but mistakenly uses 20% as one of the available solutions, instead of 30%.</s> 
With desired solution % being 50, and available solution %s being 30 and 80, correct amount of 80% solution to mix is: {{{highlight_green(matrix(1,2, 28, L))}}}.