Question 355589
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<font color=red size=4>Answers</font>
(a) <font color=red size=4>0.24</font>
(b) <font color=red size=4>0.76</font>



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Work Shown


Part (a)


P(A intersection B) = P(A)*P(B) ... only works if A and B are independent


P(A intersection B) = 0.4*0.6


P(A intersection B) = 0.24


Note: the other tutor seemed to have mixed up some formulas. Perhaps they were thinking about P(A union B) = P(A)+P(B). This formula only works if A and B are disjoint or mutually exclusive.


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Part (b)


P(A union B) = P(A) + P(B) - P(A intersection B)


P(A union B) = 0.4 + 0.6 - 0.24


P(A union B) = 0.76
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