Question 1159200
assuming given log base {{{3}}}


{{{f(x) = (1/3 )log(3,(1/4)) + log(3,(x))}}}

{{{f(x) = (1/3 )(log(3,(1))-log(3,(4))) + log(3,(x))}}}........{{{log(3,(1))=0}}}

{{{f(x) = (1/3)(-log(3,(4))) + log(3,(x))}}}


{{{f(x) = -(1/3 )log(3,(4)) + log(3,(x))}}}


{{{f(x) =  log(3,(x))-(1/3 )log(3,(4)) }}}.......change to base {{{10}}}


{{{f(x) = log((x))/log((3))-(1/3 )(log((4))/log((3)))}}}


{{{f(x) = log((x))/log((3))-log((4))/3log((3))}}}


{{{f(x) = log((x))/log((3))-(2log(2))/(3log(3))}}}


domain:

{ {{{x}}} element {{{R}}} : {{{x>0}}} } (all positive real numbers)
(assuming a function from reals to reals)