Question 1159157
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In a quadratic equation {{{ax^2+bx+c=0}}}, the sum of the roots is -b/a and the product of the roots is c/a.<br>
The product of the two roots is 50, so the other root is {{{50/(-7+i) = (-7-i)}}}<br>
The sum of the two roots is -14; the sum of the roots is also -a. So a = 14.<br>