Question 1159111


a.

{{{sum( 4^(n-1), n=1,7)=4^6+4^5+4^4+4^3+4^2+4^1+4^0=5461}}}

d.

 {{{sum( (3/2)^(n-1), n=1,10)=(3/2)^9+(3/2)^8+(3/2)^7+(3/2)^6+(3/2)^5+(3/2)^4 +(3/2)^3+ (3/2)^2+(3/2)^1+(3/2)^0=58025/512=113.33}}}