Question 1159109
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If 3 ft squares are cut from the corners, then the depth of the resulting box must be 3 feet, hence the area of the bottom of the box must be the volume divided by 3.  Then the measure of the width of the box, given that the base must be square because you started with a square piece of metal, is the square root of the volume divided by 3.  Then, before the edges were turned up, the amount that remained to turn up was 3 feet plus 3 feet less than the original dimensions of the square sheet of metal.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \sqrt{\frac{108}{3}}\ +\ 6]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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