Question 1158993
Two of the tangents to a circle meet at Q, which is 25 cm from the center.
 The circle has a 7-cm radius.
 To the nearest tenth of a degree, find the angle formed at Q by the tangents.
:
The tangent point on the circle forms a right angle with radius, a right triangle is formed with half the angle at Q and 25 cm
Find half the angle (A) at Q using the tangent of the angle
tan(A) = {{{7/25}}}
A = 15.64
then
2*15.64 = 31.3 is the angle at Q