Question 1159032

c. 

{{{sum( 2(-2/3)^n, n=0,infinity)}}}........the series has positive and negative elements, check for conditional absolute convergence->converges (absolutely )

= {{{6/5=1.2}}}
  

d. 

{{{sum( 4(0.2)^n, n=0,infinity)}}}...apply the constant multiplication rule 

={{{4*sum( 4(0.2)^n, n=0,infinity)}}} .......apply series geometric test: {{{1.25}}}

={{{4*1.25}}}

={{{5}}}