Question 1157956
a)Population decreased 4.65% per year; -4.65%= -.0465
To determine how much of the population remains per year, subtract 4.65%(-.0465) from the total population of 100% or 1. 
1-.0465=.9535
t=# of years after 2010


Answer: P(t)= 650,000(.9535)^t 


b) 2020-2010= 10 (2020 is 10 years after 2010, so t=10)
P(t)=650,000(.9535)^10 is approximately 403,757


c) 300,000= 650,000(.9535)^t
300,000/650,000=(.9535)^t
(Use logarithm to figure out t on calculator)
log base .9535 of 300,000/650,000 equals t

{{{log .9535(300000/650000)=t}}}
t is approximately 16.2 years