Question 1158967
Find the fifth term of the sequence. 

a(n) = 4a[(sub)n-1]+3, a(1) = 3

(n-1) is in subscript after 4a. I hope that makes sense. I tried using some of the formulas that I was given in class and can't seem to find one that works for me. Thank you so much in advance. <3
<pre>{{{matrix(2,3, a[n], "=", 4a[n - 1] + 3, a[1], "=", 3)}}}      {{{matrix(5,3, a[n], "=", 4a[n - 1] + 3,
a[2], "=", 4a[(2 - 1)] + 3,
a[2], "=", 4a[1] + 3,
a[2], "=", 4(3) + 3,
a[2], "=", 15)}}}       {{{matrix(5,3, a[n], "=", 4a[n - 1] + 3,
a[3], "=", 4a[(3 - 1)] + 3,
a[3], "=", 4a[2] + 3,
a[3], "=", 4(15) + 3,
a[3], "=", 63)}}}       {{{matrix(5,3, a[n], "=", 4a[n - 1] + 3,
a[4], "=", 4a[(4 - 1)] + 3,
a[4], "=", 4a[3] + 3,
a[4], "=", 4(63) + 3,
a[4], "=", 255)}}}
Have you gotten the gist of this yet?