Question 1158945
An object is thrown upward at a speed of 91 feet per second by a machine from a height of 15 feet off the ground. The height h of the object after t seconds can be found using the equation h = − 16t^2 + 91t + 15

When will the height be 102 feet?
h = − 16t^2 + 91t + 15 = 102
Solve for t
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When will the object reach the ground?
h = − 16t^2 + 91t + 15 = 0
Solve for t