Question 1158950
{{{f(x) = 1/(6x+6)}}}

the only value of {{{x}}} not in the domain is the value which makes denominator equal to zero

{{{6x+6=0}}}

{{{6x=-6}}}

{{{x=-6/6}}}

{{{x=-1}}}

so, the only value of {{{x}}} not in the domain is {{{-1}}}


{ {{{x}}} element {{{R}}} : {{{x<>-1}}} }