Question 1158882
np=mean or 0.71*145=102.95
the variance is np(1-p) or 102.95*0.29=29.855
without rounding, sqrt(V)=sd or 5.4640
want the z-score of 103.5 which will include 104 but not 103.
z=(103.5-102.95)/5.4640
=0.100659
want the probability greater than z, which is  0.4599
The actual result is 0.4650