Question 1158898
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If you have 6 friends, there are 6 ways to choose the first person who comes with you.  For each of those 6, there are 5 ways to choose the second person.  Hence there are 6 X 5 = 30 ways to choose the first two.  Then, for each of those 30 ways to choose the first two, there are 4 ways to choose the third person...and so on.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6\ \times\ 5\ \times\ 4\ \times\ 3]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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