Question 1158821
Both planes were headed on the same route from Alaska to Hawaii.  Plane #1 traveled at 520 Km/h and plane #2 traveled at 580 km/h.  If plane #1 took off 1 1/2 hours before plane #2, how many hours did it take for plane #2 to catch plane #1?
<pre>Let time plane #2 takes to get to the catch-up point, be T
Then time plane #1 takes to get to the catch-up point is, {{{matrix(1,4, T + 1&1/2, ",", or, T + 3/2)}}}
We then get the following DISTANCE equation: {{{matrix(1,3, 520(T + 3/2), "=", 580T)}}}
520T + 3(260) = 580T
3(260) = 580T - 520T
3(260) = 60T
Time plane #2 takes to catch up to plane #1, or {{{highlight_green(matrix(1,6, T, "=", 3(260)/60, "=", 13, hours))}}}