Question 15883
 Let the number =x
 its reciprocal is 1/x
  sum of the two numbers is = x+(1/x) = 10/3
   (x^2+1)/x = 10/3
   3*(x^2+1)=10*x
  3x^2-10x+3 = 0...find 2 factors of 3*3=9 whose sum is -10 ... like -9 and -1
  3x^2 -9x-x+3=0
  3x*(x-3)-1*(x-3) =0
   (3x-1)(x-3)=0
   hence 3x-1 = 0   OR    x-3 =0 
     3x=1           OR    x=3
     x=1/3          OR    x=3