Question 1158750
<u>With the wind:</u>
Distance = 840
Rate = d/t = 420
Time = 2
<pr>
<u>Against the wind:</u>
Distance = 840
Rate = d/t = 168
Time = 5
<pr>
Let s = rate in still air
Let w = speed of wind
<pr>
s + w = 420
s - w = 168
<pr>
2s = 588
<pr>
s = 294
<pr>
If s = 294, and s + w = 420, then w = 126
<pr>
s = rate in still air = 294
w = speed of wind = 126