Question 1158717

{{{y^2+ 6y = 7}}}

{{{y^2+ 6y -7=0}}}.......factor completely, write {{{6y}}} as {{{-y+ 7y}}}

{{{y^2-y+ 7y -7=0}}}.......group

{{{(y^2-y)+ (7y -7)=0}}}

{{{y(y-1)+ 7(y -1)=0}}}


{{{(y+ 7)(y -1)=0}}}


solutions:

if {{{(y+ 7)=0}}}->{{{y=-7}}}

if {{{(y -1)=0}}}->{{{y=1}}}