Question 1158583
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Triangles ADC and ABC have COMMON altitude; therefore, the ratio of their areas is the same as the ratio of their bases |AD| : |BC| = {{{3/5}}}.


Since the sum od the areas of these triangles is 3440 square inches, 


    the area of the triangle ADC is  {{{(3/(3+5))*3440}}} = {{{(3/8)*3440}}} = 1290 sq. inches;


    the area of the triangle ABC is  {{{(5/(3+5))*3440}}} = {{{(5/8)*3440}}} = 2150 sq. inches.
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Solved.


Do not accept any other answer.


What is written in the post by @mananth, &nbsp;is &nbsp;&nbsp;<U>W R O N G</U>&nbsp;&nbsp; from the first line to the end.