Question 1158689

given: {{{5(x-2)^2=125}}}

{{{5(x-2)^2=125}}}.........both sides divide by{{{ 5}}}

{{{(x-2)^2=25}}}........take sqrt of both sides 

{{{sqrt((x-2)^2)=sqrt(25)}}}

{{{x-2=sqrt(25)}}}

{{{x-2}}}=±{{{5}}}

solutions:

{{{x-2=5}}}->{{{x=5+2}}}->{{{highlight(x=7)}}}
{{{x-2=-5}}}->{{{x=-5+2}}}->{{{highlight(x=-3)}}}