Question 1158688
Let the length and width of the rectangle be l and w, respectively. We have {{{system(w=l-16,lw=10)}}}. Substituting l-16 for w in the second equation, we get {{{l(l-16)=10}}}. Expanding and rearranging, we get {{{l^2-16l-10=0}}}. *[invoke complete_the_square 1,-16,-10] We pick the positive solution, {{{x=8+sqrt(74)}}}. So the length is {{{8+sqrt(74)}}}. The width is {{{(8+sqrt(74))-16=sqrt(74)-8}}}.