Question 107398
let the amount you invest at 85% be x. So the amount you invest at 6% is (14000-x)

{{{(14000-x)*6/100+x*8/100=1060}}}

{{{840-(6x)/100+(8x)/100=1060}}}

{{{840+(2x)/100=1060}}}

{{{(2x)/100=200}}}

x=11000
this is the amount inveated at 8%. So the amount invested at 6% is $3000