Question 1158638
{{{ (1/m) (alpha)(1/n^2)}}}


{{{ (1/m) =(k/n^2)}}}

m=2,n=2

{{{(1/2) = (k/2^2)}}}

k=2 {{{n= sqrt(2)}}}


{{{(1/m) = (2/(sqrt(2^2)))}}}

m=1