Question 1158622
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(y)\ =\ \frac{-3}{y^4}\ =\ -3y^{-4}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ F(y)\ =\ \int\,-3y^{-4}\,dy\ =\ y^{-3}\ +\ C\ =\ \frac{1}{y^3}\ +\ C]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ F'(y)\ =\ -3y^{-4}\ +\ 0\ =\ \frac{-3}{y^4}\ =\ f(y)]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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