Question 1158609

I am a rectangular picture frame.if I were straight.I would be 120 inches long.


=> perimeter is 

{{{P=2(L+W)=120in}}}........eq.1

I am wrapped around a picture and my length is twice as long as my width

{{{L=2W}}}.......eq.2

first find dimensions:

{{{2(L+W)=120in}}}

{{{L+W=60in}}}........substitute in {{{L=2W}}}

{{{2W+W=60in}}}

{{{3W=60in}}}

 {{{W=20in}}}


substitute back in {{{L=2W}}}

{{{L=2*20in}}}

{{{L=40in}}}

 the area of the picture that I am wrapped around is:

{{{A=L*W}}}

{{{A=40in*20in}}}

{{{A=800in^2}}}