Question 1158584
Using Desmos to make a graph, we get <img src= https://imgur.com/download/BhRWI4R/>. <br/> {{{system(y=2x-5,x^2+y^2=5)}}}. Substituting 2x-5 for y in the second equation, we get {{{x^2+(2x-5)^2=5}}}. Expanding, we get {{{5x^2-20x+25=5}}}. Dividing both sides by 5 we get {{{x^2-4x+5=1}}}. {{{(x-2)^2=0}}}. So x=2 and plugging in to the first equation, we get y=-1. So the two graphs intersect at only one point and that point is (2,-1). The slope of the segment between (0,0) and (2,-1) is {{{-1/2}}}. {{{-1/2*2=-1}}}. This means that the segment and the line are perpendicular. The graph with the segment is <img src= https://imgur.com/download/HOrg0Xs/>