Question 1158587


an equation for the circle is:

{{{(x-h)^2+(y-k)^2=r^2}}}

if the circle is centered at ({{{-4}}}, {{{5}}}) , {{{h=-4}}} and {{{k=5}}}

{{{(x-(-4))^2+(y-5)^2=r^2}}}

{{{(x+4)^2+(y-5)^2=r^2}}}

if the circle tangent to the {{{x}}}-axis, radius is equal to the distance of the center from  the {{{x}}}-axis which is {{{5}}}


{{{(x+4)^2+(y-5)^2=5^2}}}

{{{(x+4)^2+(y-5)^2=25}}}


{{{drawing ( 600, 600, -10, 10, -10, 10,
circle(-4,5,.12),locate(-4,5,C(-4,5)),
graph( 600, 600, -10, 10, -10, 10, sqrt(-(x+4)^2+25)+5,- sqrt(-(x+4)^2+25)+5)) }}}