Question 1158436
{{{drawing(400,400,-13,3,-3.5,12.5,
grid(1),
line(-11,2,-9,8),
line(-7,4,-9,8),
line(-7,4,-5,8),
line(-5,8,-3,2) )}}}
<pre>
Your answer will have this form

{{{f(x)=system(matrix(4,3,

"______",for, "__"<=x<"__",
"______",for, "__"<=x<"__",
"______",for, "__"<=x<"__",
"______",for, "__"<=x<="__"))}}} 

where you will fill in the blanks with the four expressions
that you get for y when finding the equations of the line 
segments with their end-points.  I'll find the first 
expression for you and fill in the first blank.

The far left leg of the "M" is the line segment connecting
the points (-11,2) and the point (-9,8).

We use the slope formula and the point-slope formula.

{{{m=(y[2]-y[1])/(x[2]-x[1])=((8)-(2))/((-9)-(-11))=(8-2)/(-9+11)=6/2=3}}}

Then

{{{matrix(5,3,
y-y[1],""="",m(x^""-x[1]),
y-(2),""="",3(x-(-11)^""),
y-2,""="",3(x^""+11),
y-2,""="",3x+33,
y,""="",3x+33)}}}

So we fill in the first blank this way. In the first blank
we put what y equals, 3x+33, for the first line segment.  Then on
the left side of the inequality we put the x-coordinate of
the left-most endpoint of the line segment. On the right side of
the inequality we put the x-coordinate of the right-most endpoint 
of the line segment.

{{{f(x)=system(matrix(4,3,

3x+33,for, -11<=x<-9,
"______",for, "__"<=x<"__",
"______",for, "__"<=x<"__",
"______",for, "__"<=x<="__"))}}}

Now you fill in the other blanks the same way.

Edwin</pre>