Question 1158453
The cyclist originally traveled x km/h. It takes him {{{60/x}}} hours to travel 60 km. If he travels (x-2) km/h, it will take him {{{60/(x-2)}}} hours, which is equal to {{{60/x+1}}}. {{{60/x+1=60/(x-2)}}} Multiplying both sides by {{{x(x-2)}}}, we get {{{60(x-2)+x(x-2)=60x}}}. <br/> {{{60x-120+x^2-2x=60x}}}. {{{x^2-2x-120=0}}}*[invoke complete_square "x",1,-2,-120] <br/> A speed can't be negative, so his original speed is 12 km/hr.