Question 1158389
Let q and d be the amount of quarters and dimes she has, respectively. We have {{{system(25q+10d=1600,d=(5/2)q)}}} Rearranging, we have {{{system(10d+25q=1600,d-(5/2)q=0)}}}.<br/> *[invoke linear_substitution "d", "q", 10,25,1600,1,-2.5,0] <br/> She has 32 quarters.