Question 1158342
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<pre>

The consecutive integers are n and (n+1).


The equation, according to the condition, is

    4n + 5*(n+1) = 77.


It gives

    4n + 5n + 5 = 77

    9n          = 77 - 5 = 72

    n                    = 72/9 = 8.


<U>ANSWER</U>.  the integers are 8 and 9.
</pre>

. . . . . . . . 


Actually, this formulation is <U>provocative</U>.


It is provocative, because the notion "one number" is not the same as the "smaller number".


Therefore, in parallel with the equation (1), we should consider the other case


&nbsp;&nbsp;&nbsp;&nbsp;    4*(n+1) + 5*n = 77.


<pre>
It gives

    4n + 4 + 5n = 77

    9n          = 77 - 4  = 73

     n                    = 73/9  is not an integer number, so we reject this case.
</pre>

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Completed and solved.