Question 1158231
assuming randomness, this is a one-sample proportion
z=(p hat-p)/sqrt (p*(1-p)/n)
=-0.05/sqrt(.41*.59/100)
=0.3078
C
Note: I interpret this as a two way test. Nowhere did it say "at least 41%" but only 41%. If it were a one way test, the p-value would be half of this.