Question 1158326

Find the equation of the line that passes through the point ({{{-8}}},{{{ 3}}}) and has a slope that is 3 
4

 assuming that given slope is {{{m=3/4}}}

equation in slope-intercept form will be:

{{{y=mx+b}}}.......substitute slope and given point

{{{3=(3/4)(-8)+b}}}...........solve for {{{b}}}

{{{3=-24/4+b}}}

{{{3+24/4=b}}}

{{{b=12/4+24/4}}}

{{{b=36/4}}}

{{{b=9}}}

your equation is: {{{y=(3/4)x+9}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(-8,3,.12),locate(-8,3,p(-8,3)),
 graph( 600, 600, -10, 10, -10, 10, (3/4)x+9)) }}}