Question 107314
Almost. A couple of mistakes. 

{{{4y = 3x + 11}}}
{{{cross(4)y/cross(4)=(3x+11)/4}}}
{{{y=(3x)/4+11/4}}}
You went from 3x to -3x/4 when you divided by 4. It should remain positive. 
Also, you didn't distribute the division by 4 to the 11. 
You can always check your result using the original equation and the derived equation. 
Choose x=0 and use your original equation.
{{{4y = 3x + 11}}}
{{{4y = 3(0) + 11}}}
{{{4y =11}}}
{{{highlight(y = 11/4)}}}
With your equation
{{{y = -3/4x + 11}}}
{{{y=-3/4(0)+11}}}
{{{y=11}}}
With the revised equation,
{{{y=(3x)/4+11/4}}}
{{{y=3(0)/4+11/4}}}
{{{highlight(y=11/4)}}}