Question 107311
Your answers to a and b are correct.  We usually write them thus:
a. f(0) = 10

b. f(5) = 0

but in part c., while you had the right idea, your arithmetic was a little off!
Let's go through it.
c. 
{{{f(-2) = (-2)^2-7(-2)+10}}} 
{{{f(-2) = 4-(-14)+10}}} Recall that a positive 7 times a negative 2 = -14
{{{f(-2) = 4+14+10}}}
{{{f(-2) = 28}}}