Question 1158100

If the center of a hyperbola with a horizontal transverse axis is ​({{{2}}},{{{6}}}​), then 
one vertex is at ({{{a+2}}},{{{ 6}}}), and the other is at ({{{-a+2}}}, {{{6}}})


since {{{a^2=49}}}->{{{a=7}}}, the vertices are {{{ 7}}} units to either side, then they are at 

({{{7+2}}}, {{{6}}})=({{{9}}},{{{6}}}) and at 
({{{-7+2}}}, {{{6}}})=({{{-5}}},{{{6}}})