Question 1158056

{{{x+4y=-10}}}........eq.1
{{{2x-y=7}}}........eq.2
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{{{x+4y=-10}}}........eq.1, solve for {{{x}}}

{{{x=-10-4y}}}........eq.1a..............substitute in eq.2

{{{2(-10-4y)-y=7}}}........eq.2, solve for {{{y}}}

{{{-20-8y-y=7}}}

{{{-9y=7+20}}}

{{{-9y=27}}}

{{{y=27/-9}}}

{{{y=-3}}}

go to

{{{x=-10-4y}}}........eq.1a, substitute {{{y}}}


{{{x=-10-4(-3)}}}

{{{x=-10+12}}}

{{{x=2}}}


{{{ graph( 600, 600, -10, 10, -10, 10, 2x-7, -x/4-10/4) }}}