Question 1157987
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The point lies on the parabola if the distance from the point to the focus is equal to the distance from the point to the directrix.<br>
The distance from (1,11) to (0,4) is {{{sqrt(1^2+7^2) = sqrt(50) = 5sqrt(2)}}}<br>
To find the distance from (1,11) to the directrix y=x, use the point-to-line distance formula.<br>
{{{abs((1-11)/sqrt(1^2+1^2)) = 10/sqrt(2) = 5sqrt(2)}}}<br>
ANSWER: Yes, the point (1,11) is on that parabola.<br>